Comments on: Basic Steps to Plan Your Residential Solar Energy System http://www.residentialsolarpanels.org/plan-solar-system Wed, 09 Jun 2010 12:31:05 +0000 http://wordpress.org/?v=abc hourly 1 By: Wouter http://www.residentialsolarpanels.org/plan-solar-system/comment-page-1#comment-904 Wouter Fri, 21 May 2010 11:32:32 +0000 http://www.residentialsolarpanels.org/?p=115#comment-904 This is amazing information. THank you so much! This is amazing information. THank you so much!

]]> By: admin http://www.residentialsolarpanels.org/plan-solar-system/comment-page-1#comment-815 admin Thu, 18 Feb 2010 19:39:11 +0000 http://www.residentialsolarpanels.org/?p=115#comment-815 Ooops sorry forgot to deleted this. Now it's ok. Much Thanks Ooops sorry forgot to deleted this.

Now it’s ok.

Much Thanks

]]> By: C Purvis http://www.residentialsolarpanels.org/plan-solar-system/comment-page-1#comment-814 C Purvis Thu, 18 Feb 2010 18:30:50 +0000 http://www.residentialsolarpanels.org/?p=115#comment-814 There is a mistake in the calculations. you use the standard size of a solar panel 2m^2, to get your 47. So it is incorrect to then divide the 47 by 2 - the standard size of a panel to determine how many panels. The way you calculated it, you would need 47 standard size panels (that are 2m^2 each) 5 (Solar Radiation) x 2 (Surface Area of standard solar panels) x 0.07 (Solar Panel Efficiency) x 30.42 (Average n° of days per month) = 21.294 kWh produced per panel each month. To cover at 100% the month Kw usage of 1000Kw divide 1,000/21.294 = 47, so you would need 47 m² of panels to completely eliminate your electricity bill. This means You’ll need 24 solar panels of 2 m² each (2 m² is the standard size of solar panels) - no, you are dividing it twice. But, great info otherwize.... I also don't see where the previous commenters got 70%, all i see is .07 which is 7%. Thanks There is a mistake in the calculations. you use the standard size of a solar panel 2m^2, to get your 47. So it is incorrect to then divide the 47 by 2 – the standard size of a panel to determine how many panels. The way you calculated it, you would need 47 standard size panels (that are 2m^2 each)
5 (Solar Radiation) x 2 (Surface Area of standard solar panels) x 0.07 (Solar Panel Efficiency) x 30.42 (Average n° of days per month) = 21.294 kWh produced per panel each month.

To cover at 100% the month Kw usage of 1000Kw divide 1,000/21.294 = 47, so you would need 47 m² of panels to completely eliminate your electricity bill.

This means You’ll need 24 solar panels of 2 m² each (2 m² is the standard size of solar panels) – no, you are dividing it twice.

But, great info otherwize…. I also don’t see where the previous commenters got 70%, all i see is .07 which is 7%. Thanks

]]> By: Greg Emmet http://www.residentialsolarpanels.org/plan-solar-system/comment-page-1#comment-795 Greg Emmet Sun, 27 Dec 2009 19:25:21 +0000 http://www.residentialsolarpanels.org/?p=115#comment-795 Agreed with tuireo...the only solar panels remotely approaching that efficiency are space-based. Terrestrial solar panels are not that powerful. :D References: http://www.solarpanelnexus.com/ Agreed with tuireo…the only solar panels remotely approaching that efficiency are space-based. Terrestrial solar panels are not that powerful. :D

References:

http://www.solarpanelnexus.com/

]]> By: tuireo http://www.residentialsolarpanels.org/plan-solar-system/comment-page-1#comment-729 tuireo Tue, 03 Nov 2009 20:30:47 +0000 http://www.residentialsolarpanels.org/?p=115#comment-729 where did you get your 70%?!?!?! the efficiency of solar are not rather 10 to 15% ? where did you get your 70%?!?!?!
the efficiency of solar are not rather 10 to 15% ?

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